Answer number 8 please. Thank you.

Using the midline property;

[tex]2wy = vz[/tex]

[tex]2(p - 21) = p - 7[/tex]

[tex]2p - 42 = p - 7[/tex]

[tex]2p - p = - 7 + 42[/tex]

[tex]p = 35[/tex]

Answer:

50.29in

Step-by-step instructions:

First find the semi-circular part:- 1/2×2πr

=1/2×2×22/7×9

=28.29

Find whole perimeter:- 28.29+5+5+12 = 50.29 in

Answer:

2x8=16 so there for y=x^18

Step-by-step explanation:

Answer: 0.27

Population density of the species in water:

Population density of a species in the water is given by the expression,

       Density =Given in the question,

Number of goldfish in the tank = 12

Volume of the tank = 45 cubic feet

Substitute these values in the expression,

Density =

            = 0.267

            ≈ 0.27 goldfish per cubic feet

      Therefore, density of the tank will be 0.27 goldfish per cubic feet.

As per linear equation, there are 372 more girls in school than boys.

"A linear equation is an equation in which the highest power of the variable is always 1. It is also known as a one-degree equation. The standard form of a linear equation in one variable is of the form Ax + B = 0. Here, x is a variable, A is a coefficient and B is constant."

Given, there are 1970 pupils.

There are 799 boys in the school.

Therefore, the number of girls in the school is

[tex]= (1970-799)\\= 1171[/tex]

Therefore, the number of girls more than boys in the school is

[tex]= (1171-799)\\= 372[/tex]

In that school , there are 372 more girls than total number of the boys.

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Answer: 44 degrees

Step-by-step explanation:

Answer:

20% of 30

= 20/100 * 30

= 6

hence 6 students recieved A grade

#1

First the rectangle

Area

For semicircle

Area

Total area

#2

Area:-

[tex](\stackrel{x_1}{4}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{6}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{6}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{7}-\underset{x_1}{4}}}\implies \cfrac{6}{3}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{2}(x-\stackrel{x_1}{4})\implies y = 2x-8[/tex]

What is it?

The IQR describes the middle 50% of values when ordered from lowest to highest. To find the interquartile range (IQR), ​first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

How do you find IQR?

Step 1: Put the numbers in order. ...

Step 2: Find the median. ...

Step 3: Place parentheses around the numbers above and below the median. Not necessary statistically, but it makes Q1 and Q3 easier to spot. ...

Step 4: Find Q1 and Q3. ...

Step 5: Subtract Q1 from Q3 to find the interquartile range.

Answer:

The answer to this quesion is a measure of statistical dispersion, the spread of data or observations, first you need to get the data find the median calculate the median from both lower and upper half of the data and the iqr is the diffrence between the lower and upper.

Step-by-step explanation:

I Hope This Helps You!

-Justin:)

The function is given by y = 550(0.76)ˣ, after 10 passes, the number of dirts is about 35.36 ml

Let y represent the amount of dirt on the floor after x passes.

The floor initially has 550 ml of dirt, hence a = 550.

During each pass, 24% of the dirt is removed. Hence b = 100% - 24% = 76% = 0.76

The equation is given by:

y = 550(0.76)ˣ

After 10 passes:

y = 550(0.76)¹⁰ = 35.36 ml

The function is given by y = 550(0.76)ˣ, after 10 passes, the number of dirts is about 35.36 ml

Find out more on exponential function at: https://brainly.com/question/12940982

Answer:

483

Step-by-step explanation:

I really really pray and hope this helpss.

Answer:

X=3(7+23)

Step-by-step explanation:

Answer:

Step-by-step explanation:

Notation for Cereal Set Roster

The roster form is one of the simplest ways to represent the set. The elements of a set are represented in a row and separated by a comma in roster form. For example, the first five positive even numbers are denoted as A = 2, 4, 6, 8, 10.

A = 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100 is an example of roster notation: A = 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100.

Hope that helps you understand :)

Answer:

v = 118.333333333

Step-by-step explanation:

formula: V=a^2h/3

The area is the base edge (so 5)

The height is the line going up the triangle (14.2)

Fill in:

v = 5^2(14.2/3)

Solve:

exponent first: 5^2 = 25

v = 25 (14.2/3)

divide/find out fraction: 14.2/3 = 4.73333333333

v = 23 x 4.73333333333

multiply: 23 x 4.73333333333 = 118.333333333

v = 118.333333333

you can also write as v = 118.3 with a line like “-“ over 3 to show the 3 is repeating:)

Answer: X-axis

Step-by-step explanation: The arrow is pointing to the horizontal line on the on the graph. That horizontal line is the x-axis.

Answer:

2/5 > 1/4

Step-by-step explanation:

First convert the denominators to the LCM which will be 20

2/5 will convert to 8/20 because 5 x 4 = 20 so 2 x 4 = 8 and 1/4 will convert to 5/20 because 4 x 5 = 20 so 1 x 5 = 5

Answer:

9.09

Step-by-step explanation:

[tex]\frac{0.81}{0.09} + \frac{0.81}{9}[/tex]

= 9 + [tex]\frac{0.81}{9}[/tex]

= 9+ 0.09

= 9.09

I hope this helped!! If so please rate and mark brainliest <3!!

Answer:

t = 0, and t = 4/5

Step-by-step explanation:

1. Write the equation in standard form:

-75t^2+60t=0

2. Solve with the Quadratic formula:

[tex]t_{1,2} = \frac{-60 +- \sqrt{60^2 - 4(-75)}0}{2(-75)} \\\\t_{1,2} = \frac{-60+-60}{2(-75)} \\\\3. Separate the fractions:\\t_{1} = \frac{-60+60}{2(-75)} , t_{2} = \frac{-60-60}{2(-75)} \\\\4. Solve for each:\\t_{1} = \frac{0}{-150} = 0\\t_{2} = \frac{-120}{-150} = 4/5[/tex]

hope this helps!

Answer:

2 semi circles put together

Step-by-step explanation:

just cut the circle in half

Answer:

Third option

Step-by-step explanation:

Given the following question:

[tex]7x-4=5x+15[/tex]

To find the answer we need to use inverse of operations to simplify the equation in till we isolate the variable and find the value of x.

[tex]7x-4=5x+15[/tex]
[tex]-4+4=0[/tex]
[tex]15+4=19[/tex]
[tex]7x=5x+19[/tex]
[tex]5x-5x=0[/tex]
[tex]7x-5x=2x[/tex]
[tex]2x=19[/tex]
[tex]2x\div2=x[/tex]
[tex]19\div2=\frac{19}{2}[/tex]
[tex]=\frac{19}{2}[/tex]

Your answer is the third option or "19/2."

Hope this helps.

Answer:

App. 83.33 kg

Step-by-step explanation:

10/60=0.167 kg/minute

0.167/3=0.056 kg/minute/person

0.056 x 25 x 60= 83.33...6

Answer:

6.0 ft^2

Step-by-step explanation:

hope this helps

Hey so I have a question do u need to explain?

Answer:

25°

Step-by-step explanation:

51+x+14=90°

x+65=90°

x=90-65

x=25°

Answer: 25°

Step-by-step explanation:

51+x+14=90°

x+65=90°

x=90-65

x=25°

The cosine function for the ferris wheel ride is an illustration of a sinusoidial function

The equation of the Ferris wheel is y = -190cos(π / 120 t) + 195

A cosine function is represented as:

y = Acos(Bt - C) + D

From the complete question, the diameter of the ferris wheel is 380 feet.

The amplitude represents the radius, and this is calculated as:

A = 380/2

A = 190

The function becomes:

y = 190cos(Bt - C) + D

The period of the function is:

T = 2π / B

From the complete question, one full rotation is completed in 4 minutes.

Convert the time to seconds

T = 4 * 60

T = 240.

So, we have:

240 = 2π / B

Divide both sides by 2

120 = π / B

Make B the subject

B = π / 120

The function becomes

y = 190cos(π / 120 t - C) + D

From the question, the ferris wheel is 195 feet above the ground.

This represents the vertical shift.

So, we have:

D = 195

The function becomes

y = 190cos(π / 120 t - C) + 195

Also, we have:

The lowest point is at t = 0 and the function is a negative cosine function

So, we have:

C = 0

The function becomes

y = -190cos(π / 120 t) + 195

Hence, the cosine function is y = -190cos(π / 120 t) + 195

Read more about cosine functions at:

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Answer:

The answer is 15

Step-by-step explanation:

Answer:

[tex]x=\pm\frac{1}{2}[/tex]

Step-by-step explanation:

On a unit circle, [tex](x,y)=(\cos\theta,\sin\theta)[/tex], so [tex]\sin\theta=\frac{\sqrt{3}}{2}[/tex] in this case. If you look at the attached circle, the only time that the y-coordinate is [tex]\frac{\sqrt{3}}{2}[/tex] is when [tex]x=-\frac{1}{2}[/tex] and [tex]x=\frac{1}{2}[/tex], which correspond to angles of [tex]\theta=\frac{2\pi}{3}[/tex] and [tex]\theta=\frac{\pi}{3}[/tex] respectively